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+--- Thread: Need Help with math (/showthread.php?tid=6817)
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Need Help with math - Mirinee - 25-05-2005
whiteninja Wrote:Lines with equal slopes are parallel to each other; lines with negative reciprocals are perpendicular.Not to each other. You mean a line with gradient m is perpendicular to a line with gradient -1/m.
![[Image: silly.gif]](http://ragol.warcrafttavern.com/images/forums/smilies/silly.gif)
Eep. Converting from polar and rectangular. Um...
I hope the ones you get given are no more difficult than the example you gave.
R=cos(theta) on the polar graph (plot it
) is a circle of radius 1, its left side touching the origin, *draws*, so just look at that and say, oh, use the cartesian "equation of a circle", which is of the form((X-A)^2)+((Y-B)^2) = C^2 , like whiteninja said.
The centre would be (0.5, 0), and its radius is 1, hence
(X-0.5)^2 + Y^2 = 1.
This might be a clumsy way of doing it, but I can't think of another way off the top of my head right now ;;^_^ .
I hope you won't be given anything other than
-equation of a straight line
-equation of a parabola
-equation of a circle
Need Help with math - zero132132 - 25-05-2005
Oh but I will. They decided to give me stuff such as some four-leaf clovers and some good old hyperbolas. Thanks for the help that actually helps a little. Guess I'll just have to use the chart method.
Edit: Go ahead and shut this one down mods, I have the test in about 2 hours and I won't have time to check back here.
Need Help with math - Mirinee - 25-05-2005
They expect you to convert those into cartesian? I'd really like to know the proper way to do those problems. Would you tell me?
Anyway, good luck.
Need Help with math - zero132132 - 25-05-2005
Well... I just took it and well... I knew about half of the stuff on the test. I was a bit confused about what he was expecting us to do. All he expected us to do was to take something like y=(-1/squareroot(3))x and convert it to polar (that one turned out weird). With the graphing stuff, we had to graph cos^2(theta)=r on some weird graph dealie (bunch of circles with lines going out for all the parts of 2 pi). Oh well. Thanks for the help anyway. If I figure out how to convert the weird four-leaf clover to cartesian I'll get back to you. Don't expect it to be too soon though.
