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1/183 - Natayna - 03-06-2009
can some
one please tell me
what
Viridia, Hard Seabed, Delbiter = 1 / 46
Viridia, Very Hard Seabed, Sinow Zoa = 1 / 214
Viridia, Ultimate Seabed, Sinow Zoa = 1 / 1051
Purplenum, Very Hard Seabed, Sinow Zele = 1 / 183
Purplenum, Ultimate Seabed, Sinow Zoa = 1 / 1051
Redria, Very Hard Gal Da Val Islands, Merikle = 1 / 46
Redria, Ultimate Gal Da Val Islands, Merillia = 1 / 1051
Yellowboze, Very Hard Mine, Sinow Gold = 1 / 117
the numbers 1/117 mean D:
1/183 - K_I_R_E_E_K - 03-06-2009
1/1 means 1 chance in 1 total, so that's 100%
1/2 means 1 chance in 2, it's like fliping a coin, so it's 50%
Now you see some drop rates like 1/117, all you need is to imagine a bag that contains 116 black balls and 1 white ball, if you try to take out the white ball the chances will be 1/117.
Same thing is aplied here, keep in mind that the drop rate remains the same no matter the amout of times you try, so it's 1/117 every single time.
The more enemys (the same enemy) you kill, the more oportunities you have to get the item, that's why some ppl do specific quests because they know certain quests have a high amount of that enemy.
1/183 - Natayna - 04-06-2009
thank you very much
i though it was something so different
Thank you
now i can finally get some good weapons, maybe
1/183 - demeiz - 24-06-2009
Well it doesn't quite mean that kireek. It's like fractions..
1/4 doesn't mean every 4 times you kill the monster you will get one. It's just the lowest form of the fraction.
E.g. 1/4, 2/8, 4/16
Use it as a guideline, not a rule.
For instance i think Musashi is a 1/40 drop on hard for purpulenum, took me 60 runs to get it though.
1/183 - Natayna - 28-06-2009
ahh so if i were to run through Very Hard Mines to get db's shield,
how many times do you think i would have to run through it
to get it?
and the chances are
Purplenum, Very Hard Mine, Gillchic = 1 / 427
1/183 - pso king - 28-06-2009
Natayna Wrote:ahh so if i were to run through Very Hard Mines to get db's shield,
how many times do you think i would have to run through it
to get it?
and the chances are
Purplenum, Very Hard Mine, Gillchic = 1 / 427
there's no determination. you could get it first target even on 1/28000 whatever items or you could never get it even on 7/8 items
something might be here http://www.pso-world.com/sections.php?op=listarticles&secid=90. it said item frequency so there's a good chance you'll find what you're looking for here.
1/183 - K_I_R_E_E_K - 28-06-2009
I guess it's an average drop, you will find it faster then you think.
All i can say is good hunting.
1/183 - Natayna - 29-06-2009
Gawd. so insane D:
So for me its
Purplenum, 1/427 Db's shield, and its 30%
For damn gillchic's
FML!
i ran throught vhard mines so many times
and i canno't find one, im still on the search, is there any bettter
shields i can get ?
1/183 - whiteninja - 02-07-2009
Rare drops are a binomial distribution. In a binomial distribution, for every "event," you can have either a "success" or a "failure." In the case of PSO, an event = an enemy kill, a success = a rare drop, and a failure = no rare drop. The more events (enemy kills) you have, the more likely it is you're going to get a success (rare item), but there's no guarantee of that. You could hunt forever and never get your rare, as some players have experienced.
So, to calculate the actual odds of getting a certain number of rares after a certain number of enemy kills, you use the following formula.
P(n|N) = (N!) / (n! * (N - n)!) * p^n * (1-p)^(N-n)
P = "probability of" - it'll come out in a decimal; multiply by 100 to make it a percentage
n|N = "n successes in N tries" - that is, how many rares you want in how many enemy kills.
! = the factorial operator - basically, multiply a number by every number from it down to 1. So, 5! = 5*4*3*2*1 = 120. Also, 0! = 1 by definition.
p = the odds of a rare drop, eg. 1/2, 1/55, 1/205, 1/299594
^ = the exponent operator, like 5^3 = 5*5*5 = 125
You can see if that if n=1 and N=1, then P(n|N) = p. I also ought to note that this formula only gives the odds for that one exact pair of n|N. So, if you want to find the odds of getting at least 3 rares in some number of kills (say you need three God/Battles), then you've got to calculate P(3|N), P(4|N), P(5|N), etc. and add them all together. However, since that series goes to n = infinity, it'd be easier to simply calculate the odds of n = 0, 1, and 2, then add them together, and subtract that total from 100%.
Typically, what we care about is what are the odds of getting NO rares in some number of enemies? If we've killed 80 Pal Rappies and not gotten an Angel Harp (1/21) what are the odds of that happening? How pissed off should we be? In that case, the formula reduces to:
P(0|N) = (1 - p)^(N) = (20/21)^80 = 0.02017
That means, there's a 2.017% chance of getting no rares, and about a 98% chance that we should have gotten AT LEAST one. So, at that point, it's still not even 100%. It'll never be. But 98% is pretty damn good. You'd be happy with that score on a final exam! So, seeing as how you haven't gotten even one yet, you ought to be pretty pissed!
I hope that clears some things up!